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MasterMath

Series and Parallel Capacitor Calculator

The equivalent capacitance of several capacitors in series or in parallel. It works the opposite way round from resistors, and that is the part to keep straight.

Equivalent capacitance

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Equivalent capacitance—
Capacitors—
Smallest—
Largest—
Compared with the smallest—
#ValueIts share

How this was worked out

    The formula

    Parallel: C = C₁ + C₂ + … · Series: 1/C = 1/C₁ + 1/C₂ + …

    What it means

    A capacitor stores charge on the surface of its plates, so putting them in parallel is like widening that surface: the capacitances add. In series the opposite happens, because it is like moving the plates apart: the combination stores less than the smallest one. It is exactly the resistor rule with the roles swapped, and mixing the two up is the most repeated mistake in the topic.

    How to work it out by hand

    1. If they are in parallel, add all the capacitances
    2. If they are in series, work out the reciprocal of each one
    3. Add those reciprocals together
    4. Invert the result: that is the equivalent capacitance

    What is worth knowing

    In series there is a consequence the formula does not show: the voltage divides between the capacitors in inverse proportion to their capacitance, so the smallest one takes the most voltage and is the first to fail. That is why, when capacitors are put in series to withstand more voltage, they are chosen equal and each gets a resistor in parallel to even the share out.

    Frequently asked questions

    Why is it the opposite of resistors?

    Because a capacitor stores charge according to its plate area. Putting them in parallel adds area; putting them in series is like moving the plates apart.

    What units does it work in?

    Whatever you give it: write microfarads and you get microfarads. The calculation is a proportion.

    Two equal capacitors in series?

    Half the capacitance, and each one takes half the total voltage.

    Why do they withstand more voltage in series?

    Because the voltage divides between them. With unequal capacitances the split is uneven and the smallest one takes the worst of it.

    What is the share in the table?

    In parallel, the fraction of the charge each one stores. In series, the fraction of the voltage each one withstands.